Answer:
8
Step-by-step explanation:
Answer: 294√3
Explanation:
1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a
2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.
3) Then you can use Pythagorean theorem fo find a:
14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3
4) Therefore, the area of one triangle is: 14 × 7√3 / 2 = 49√3
5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
Answer:
3.4028 x 10^-1
Step-by-step explanation:
First you make the 9400 into scientific notation:
9.4x10^3
Then you combine like terms
(3.62x9.4)(10^-5x10^3)
Finally you simplify
34.028x10^-2
3.4028x10^-1
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Step 1
Find the length of MD
we know that
The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle
so
In this problem
------> is the radius of a circle inscribed inside the triangle
we have that

therefore


Step 2
Find the length of DC
we know that
In the right triangle MDC
Applying the Pythagoras theorem

we have


substitute



