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Lena [83]
3 years ago
8

If w = -2 and v = -8, which of the following expressions shows the values correctly substituted in for the variables in the expr

ession w2 - v + 1?
(-2) 2 - (-8) + 1
(-2) 2 - (8) + 1
-2 2 - (-8) + 1
-2 2 - 8 + 1
Mathematics
2 answers:
Cloud [144]3 years ago
7 0
It’s A (-2) 2- (-8) + 1
ki77a [65]3 years ago
3 0

Answer:

the first one

(-2) 2-(-8)+1

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4. (03.05)
Snowcat [4.5K]

Answer:

B. domain is all integers 0 through 9

Step-by-step explanation:

Domain values area usually plotted along the horizontal axis. In this case, the number of days is the domain of the of the function.

The domain of the function that is plotted on the graph ranges from 0, 1, 2 to 9.

1, 2, 3 to 9 are all integers. Therefore, we can conclude that the "domain is all integers 0 through 9."

5 0
3 years ago
Simplify (-2x-3)-(3x²-8x+9) <br>in standard form.
Musya8 [376]
(-2 x -3) - (3x^2 - 8x + 9)
     -6     -    9x - 17x
    -6          -        -8x
              -14x

hope this helps,
Batgirl12
8 0
3 years ago
Which statement correctly describes the end behavior of y = −3x5 + 5x2 +2x + 1
saveliy_v [14]
What is all the answers cause i got -98
8 0
3 years ago
(brainiest)Which letter would be the most meaningful variable for this problem situation?
dexar [7]

Answer:

  • options B

Step-by-step explanation:

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7 0
3 years ago
What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) a x = 3 p
Ratling [72]

x-coordinates for the maximum points in any  function  f(x) by f'(x) =0 would be  x = π/2 and x= 3π/2.

<h3>How to obtain the maximum value of a function?</h3>

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

we want to find x-coordinates for the maximum points in any  function  f(x) by f'(x) =0

Given f(x)= 4cos(2x -π)

f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi  = k\pi ...  k in Z

In general  x=(k+1)\pi /2

from x = 0 to x = 2π :

when k =0  then  x = π/2

when k =1  then x= π

when k =2  then x= 3π/2

when k =3  then x=2π

Thus, X-coordinates of maximum points are  x = π/2 and x= 3π/2

Learn more about maximum of a function here:

brainly.com/question/13333267

#SPJ4

4 0
2 years ago
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