D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
POINTS FOR HOW MANY?
THE ANSWER IS BRUCE
Step-by-step explanation:
-1 and 1 are opposites, not decimals, and not fractions. Please mark Brainliest!!!
Answer:
5 hours
Step-by-step explanation:
This is a classic pre-algebra question.
i believe the answer would be A.
in slope-intercept form, it's y = -3/2x - 1
