Answer: i think it's either a or d
You will need to add 3 to each side.
x^2-3=15
+3 +3
x^2=12
and go from there
Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
Answer:
Step-by-step explanation:
Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
Step 2: Use a factoring strategies to factor the problem.
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
The first question is 50% because a total of 30 girls bought lunches out of 60 kids
the second question, the easiest way is to plug in the x and y coordinates
3(4) - 2(0) = 12
12-0=12
12=12
because 12 = 12 is true, the first pair is the answer