The slope is 4/3.
rise/run
rise = 4
run = 3
Let r = radius of the circle.
The circumference is C = 2πr.
The area is A = πr^2.
Because the circumference is greater than the area, therefore
![2 \pi r\ \textgreater \ \pi r^{2}](https://tex.z-dn.net/?f=2%20%5Cpi%20r%5C%20%5Ctextgreater%20%5C%20%20%5Cpi%20%20r%5E%7B2%7D%20)
![1\ \textgreater \ \frac{ \pi r^{2} }{2 \pi r}](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%20%5Cfrac%7B%20%5Cpi%20%20r%5E%7B2%7D%20%7D%7B2%20%5Cpi%20r%7D%20)
![1\ \textgreater \ \frac{r}{2}](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%20%5Cfrac%7Br%7D%7B2%7D%20)
Therefore the radius should satisfy
r < 2
<span><span><span><span><span>−12</span><span>a3</span></span><span>b2</span></span>c</span><span><span><span><span>-12</span><span>a3</span></span><span>b2</span></span>c</span></span> out of <span><span><span><span><span><span>−24</span><span>a3</span></span><span>b3</span></span><span>c3</span></span><span><span><span><span>−84</span><span>a4</span></span><span>b2</span></span>c</span></span><span><span><span><span><span>-24</span><span>a3</span></span><span>b3</span></span><span>c3</span></span><span><span><span><span>-84</span><span>a4</span></span><span>b2</span></span>c</span></span></span>.
<span><span><span><span><span><span>−12</span><span>a3</span></span><span>b2</span></span>c</span><span>(<span><span><span>2b</span><span>c2</span></span>+<span>7a</span></span>)</span></span><span><span><span><span><span>-12</span><span>a3</span></span><span>b2</span></span>c</span><span><span><span>2b</span><span>c2</span></span>+<span>7a</span></span></span></span>