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3 years ago

8

It's never to late to go back to bed. u w u

1 answer:

Elden [556K]3 years ago

8 0

Answer:

bed

Step-by-step explanation:

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If the area of a rectangle is 12cm2 what could its length be and its width?

lawyer [7]

Hello,

We know that th formula for the area of a rectangle is: $A=b*h$
Now, the problem in this excercise is that there is no restriction on the values that b and h can take, so, they can take any value provided that it meets: $b*h=12 cm^{2}$
for example:
$lenght= \frac{12}{3}cm \,\,\,\,\,\,and\,\,\,\,width= 3 cm \\ \\ A=\frac{12}{3}cm*3cm \\ A=12 cm^{2}$

But if they can only take intenger values, what we have to do is to descompose 12, and then we can analyze the possible solutions.

12 | 2
6 | 2
3 | 3
1

12= 2 *2*3

first option:
12=4*3

Answer: lenght= 4cm and width= 3cm or vice versa

second option:
12=2*6

Answer: lenght= 6cm and width= 2cm <span>or vice versa</span>

7 0

3 years ago

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→1 1 − x + l

AfilCa [17]

$\displaystyle\lim_{x\to1}\frac{1-x+\ln x}{1+\cos5\pi x}$

Evaluating the limand directly at $x=1$ gives an indeterminate form $\dfrac00$ . Apply L'Hospital's rule once and we get

$\displaystyle\lim_{x\to1}\frac{-1+\frac1x}{-5\pi\sin5\pi x}$

Again, plugging in $x=1$ returns $\dfrac00$ . Apply the rule once more:

$\displaystyle\lim_{x\to1}\frac{-\frac1{x^2}}{-25\pi^2\cos5\pi x}=\frac1{25\pi^2}\lim_{x\to1}\frac1{x^2\cos5\pi x}$

Now, in the denominator, when $x=1$ we get $x^2\cos5\pi x=-1$ , so the limit is $-\dfrac1{25\pi^2}$ .

3 0

3 years ago

my last question was deleted for asking whats 2+2 & may i just say , i have learned from my consequence , that when im bored

castortr0y [4]

Answer:

4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help me out with thissss

vova2212 [387]

Answer:

Step-by-step explanation:

From table 1,

f(x) = bˣ

For x = -1,

f(-1) = 0.5

0.5 = (b)⁻¹

b = $\frac{1}{0.5}$

b = 2

For x = 1.585,

f(1.585) = 3

3 = $2^{1.585}$

3 = $2^{1}\times2^{0.585}$

$2^{0.585}=\frac{3}{2}$

$2^{0.585}=1.5$

For x = 2.585,

f(2.585) = $2^{2.585}$

= $2^{2}\times 2^{0.585}$

= 4 × 1.5 [Since, $2^{0.585}=1.5$ ]

= 6

From table 2,

g(x) = $\text{log}_b(x)$

For x = 0.5,

g(0.5) = -1

-1 = $\text{log}_b(0.5)$

b⁻¹ = 0.5

b = 2

For x = 2,

g(2) = 1

1 = $\text{log}_2(2)$

For x = 6,

g(6) = 2.585

2.585 = $\text{log}_2(6)$

2.585 = $\text{log}_2(2\times 3)$

2.585 = $\text{log}_2(2)+\text{log}_2(3)$

2.858 - 1 = $\text{log}_2(3)$

$\text{log}_2(3)=1.585$

For x = 3,

g(3) = $\text{log}_2(3)$

g(3) = 1.585

8 0

3 years ago

Find two numbers whose difference is 12 and whose sum is 40

riadik2000 [5.3K]

Your answer is going to be 26 and 14, because 26+14=40, and 26-14=12.:)

5 0

3 years ago