Answer:
Simplifying
5x + 7y = -6
Solving
5x + 7y = -6
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7y' to each side of the equation.
5x + 7y + -7y = -6 + -7y
Combine like terms: 7y + -7y = 0
5x + 0 = -6 + -7y
5x = -6 + -7y
Divide each side by '5'.
x = -1.2 + -1.4y
Simplifying
x = -1.2 + -1.4y
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Simplifying
4x + 7y = -9
Solving
4x + 7y = -9
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7y' to each side of the equation.
4x + 7y + -7y = -9 + -7y
Combine like terms: 7y + -7y = 0
4x + 0 = -9 + -7y
4x = -9 + -7y
Divide each side by '4'.
x = -2.25 + -1.75y
Simplifying
x = -2.25 + -1.75y
In this question it is given that
Carla earns $8.43 per hour. It means that her hourly rate is $8.43 .
And we have to find her overtime pay at time-and-a-half.
First we have to understand what time and a half means .
Time and a half means 1.5 times of the normal rate. And to find the overtime pay, we have to multiply 1.5 and normal hourly rate. That is
Therefore correct option is a .
(5,4)
On a system of 2 perpendicular axis with O as origine, the pair (5,4) means:
5 is the distance from the origin O and situated on x-axis (on the right of O)
4 is the distance from the origin O and situated on y-axis (above O)
Then the pair (5,4) is situated in the 1st Quadrant
Answer:
The length of the shorter piece=0.35 m
Step-by-step explanation:
Let the lengths be as follow;
Shorter piece=x
Longer piece=15 cm longer than twice shorter piece(x)
Since 1 m=100 cm, 15 cm=15/100=0.15 m
Longer piece= (2×x)+0.15=2x+0.15
Total length=1.2 m
Total length=shorter piece+longer piece
Replacing;
1.2=x+2x+0.15
3x=1.2-0.15
3x=1.05
x=(1.05/3)=0.35
The length of the shorter piece=x=0.35
Answer:
The hypotheses used in this situation
Step-by-step explanation:
We are given that Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.
Mean = 
Claim : The amount UMSL students study is different from this 14.6 hour benchmark.
The hypotheses used in this situation
