Answer:
59.16 units
Step-by-step explanation:
Given that,
The length of rectangle, L = 13
The breadth of the rectangle, B = 6
The perimeter of the shaded region = perimeter of rectangle - 2(perimeter of semicircle)
![P=13\times 6-[2\times \dfrac{2\pi r}{2}]\\\\=78-2\pi r\\\\=78-2\times 3.14\times 3\\\\=59.16](https://tex.z-dn.net/?f=P%3D13%5Ctimes%206-%5B2%5Ctimes%20%5Cdfrac%7B2%5Cpi%20r%7D%7B2%7D%5D%5C%5C%5C%5C%3D78-2%5Cpi%20r%5C%5C%5C%5C%3D78-2%5Ctimes%203.14%5Ctimes%203%5C%5C%5C%5C%3D59.16)
So, the perimeter of the shaded region is 59.16 units.
Answer:
1 fancy 15 plain
Step-by-step explanation:
F + P = 16
15F +10P = 165
Miltiplu the 1st by -10:
-10F -10P = -160
15F + 10P = 165
Add both (10p is cancelled)
5F = 5
F =1
16-1 = 15 (15plain)
15 x10 =150
1x15 =15
150 +15 = 165
Yes it is it would not be able to go any lower
good job :)
I think the answer is false✨
