Answer:
1. Option (a) is the correct answer. "Place a firewall between the Internet and your Web server".
2. Option (e) is the correct answer. "Require encryption for all traffic flowing into and out from the Ken 7 Windows environment".
3. Option (d) is the correct answer. "Implement Kerberos authentication for all internal servers".
4. The correct answer is option (g) "Require all personnel attend a lunch and learn session on updated network security policies".
5. Option (c) is the correct answer. "Enforce password complexity".
Explanation:
1. Users who tried to use ken 7 network resources for social media access will not be enable to do so.
2. Encryption for inflow and outflow of traffic from Ken 7 windows environment will monitor any personal devices which is connected to Ken 7 windows network.
3. The implementation of Kerberos authentication will deny anonymous users access to protected resources in Ken 7 infrastructure.
4.All personnel will be taught the network policies to avoid sending report to unsecured printers.
5. The more complex passwords are, the more secured the server will be. A complex password should be enforce for network security.
1. Motherboard (you plug all other components to it)
2. Processor (CPU)
3. Memory (RAM)
4. Graphics card
5. Sound card (sometimes integrated with motherboard)
6. Hard Disk Drive (HDD)
7. Power supply unit
Answer:
Task manager
Explanation:
Allows you to force quit applications.
Explanation:
This is easily solvable with a for loop. Something like:
(I assume c++)
#include <iostream>
#include <string>
int main() {
take_input: //tag
std::string input;
cin >> input; //take the input
int spaceCount = 0;
char checking;
for(unsigned int i = 0; i == input.length(); ++i) {
checking = spaceCount[i];
if(checking == ' ')
spaceCount++;
}
if(spaceCount >= 1 && input.length >= 5)
std::cout << "Your name is " + input;
else
goto take_input; // reasks for input if the conditions are not met
return 0;
};
**remove all spaces before using the code, the if statements are messed up
