Answer:
for (scores.Entry<String, Integer> entry : scores.entrySet()) {
int value=0; String key="Rambo";
String k = entry.getKey();
int v = entry.getValue();
if (v>value)
{
value =v;
}
else
{
value=value;
}
}
for( scores.Entry<String, Integer> entry : scores.entrySet())
{
if( entry.getValue()==value)
System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
}
Explanation:
The above scores are an object of Map type. And this is a parameter of findUopStudent function. So scores is a Map, and entry is an item. And we get its key and value. Now we compare each value using senteniel method and find the maximum value. Now we iterate through the scores using for the look and check the value of each entry against the maximum value found, and we print out the entry with maximum value. And that is the top student, which is required.
Answer: Linked cell
Explanation: I just did a test
Answer:
d. This statement results in input failure.
Explanation:
We are taking input of 3 variables only and those are x,ch,and y. cin is a C++ keyword used take input entered by the user onto the screen cin is not a variable.
The input should of type int char int as written in the code. First is x and character variable ch and then the integer variable y and there should be only three inputs.
Answer:
Option B; 30 SECONDS OR LESS.
Explanation:
Short-term memory, also known as primary or active memory, is the information we are currently aware of or thinking about.
When short-term memories are not rehearsed or actively maintained, they last mere seconds.
Most of the information kept in short-term memory will be stored for less than 30 seconds (approximately 20 to 30 seconds), but it can be just seconds if rehearsal or active maintenance of the information is not done.
Therefore, Anita likely will be able to retain the information in short-term memory, without additional processing, for 30 SECONDS OR LESS.
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