Answer:
Network topology is the arrangement of the elements (links, nodes, etc.) of a communication network. Network topology can be used to define or describe the arrangement of various types of telecommunication networks, including command and control radio networks, industrial field busses and computer networks.
Answer:
a) 255
b) 61602
c)
d)
Explanation:
You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>
For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:
a. F F
position 1 0
Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:
Finally, you'll add your results:
240+15=255
FF=255
b. F 0 A 2
position 3 2 1 0
F0A2=61602
c. F 1 0 0
position 3 2 1 0
0F100=61696
d. 1 0 0
position 2 1 0
100=256
I hope you find this information useful! Good luck!
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❖ The correct answer choice is B) sorting. When you sort, you can order your sheet however you'd like.
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Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
The correct answer to the following question will be Option D (Media).
Explanation:
Media are the contact channels or devices used to store information or data and distribute it. The phrase refers to elements of the media marketing industry such as printed media, printing, mainstream media, film, theater, television and radio broadcast, and advertisement.
There are mainly three types of media, which are as follows:
- Print media
- Broadcast media
- Internet
Using these three media, we can describe the content and the surfaces on which an artist works.
Therefore, Option D is the right answer.
