Answer:
The name of a .java file should <u>always match the name of the class inside.</u>
Explanation:
In Java programming the program written in code editor is first saved with .java extension. The name of this .java file should be same as that of the class declared inside the file.
This .java file is then compiled and converted to .class file which contains the java bytecode. This bytecode can then be executed by java virtual machine(JVM).
However it is not always necessary that name of .java files should be same as that of class inside it. The name should be same only when the class inside is declared as public.
In case it is not declared as public one can name .java file different than the actual class name.
Answer: b
The computer virus is simply a ___
b. Set of computer instructions or code
Answer:
The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".
Explanation:
In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below
(A.) The Code fragment A runs fastly than the code fragment of B.
(B.) The Code fragment B runs fastly than code fragment of A.
(C) The Code fragment A runs as fastly as code fragment of B.
So we conclude the answer i.e option(A) because As given in the question list1 is a MyArrayList and list2 is a MyLinkedList. , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.
The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then MyArrayList is a better option so the code fragment runs fastly then code fragmented B.
Answer:
C++ code is given below
Explanation:
#include <iostream>
#include <cctype>
#include <string.h>
#include <cstring>
#include <sstream>
using namespace std;
struct Car {
public:
char reportingMark[5];
int carNumber;
string kind;
bool loaded;
string destination;
};
void input(Car *);
void output(Car *);
int main() {
Car *T = new Car;
input(T);
output(T);
delete T;
return 0;
}
void input(Car *T)
{
string str, s;
cout << " Enter the reporting mark as a 5 or less character uppercase string: ";
cin >> str;
for (int i = 0; i < str.length(); i++)
T->reportingMark[i] = toupper(str[i]);
cout << " Enter the car number: ";
cin >> T->carNumber;
cout << " Enter the kind: ";
cin >> T->kind;
cout << " Enter the loaded status as true or false: ";
cin >> s;
istringstream(s) >> boolalpha >> T->loaded;
if (T->loaded == true) {
cout << " Enter the destination: ";
cin.ignore();
getline(cin, T->destination);
}
else
T->destination = "NONE";
}
void output(Car *T)
{
cout << " Reporting Mark: " << T->reportingMark;
cout << " Car Number: " << T->carNumber;
cout << " Kind: " << T->kind;
cout << " Loaded Status: " << boolalpha << T->loaded;
cout << " Destination: " << T->destination << " ";
}
Answer:
Software for personal computers is typically developed and distributed independently from the hardware or operating system manufacturers. Many personal computer users no longer need to write their own programs to make any use of a personal computer, although end-user programming is still feasible. This contrasts with mobile systems, where software is often only available through a manufacturer-supported channel. And end-user program development may be discouraged by lack of support by the manufacturer.
Explanation:
