(a) For series circuit, current in 14 ohms = current in 72 ohms = 0.698 A
(b) Power loss in each series resistor, 14 ohms = 6.82 W and 72 ohms = 35.1 W.
(c) For parallel circuit, current in 14 ohms = 4.29 A and current in 72 ohms = 0.83 A
(d) Power loss in each parallel resistor, 14 ohms = 257.4 W and 72 ohms = 49.8 W.
<h3>Current in each series resistors</h3>
The total resistance = R1 + R2
R = 14 + 72 = 86 ohms
Current = V/R = 60/86 = 0.698 A
Since the resistors are in series, current in 14 ohms = current in 72 ohms = 0.698 A
<h3>Power loss in each series resistor</h3>
P = I²R
P(14 ohms) = (0.698)² x 14 = 6.82 W
P(72 ohms) = (0.698)² x 72 = 35.1 W
<h3>Current in each resistor for parallel arrangement</h3>
Total resistance, 1/R = 1/R1 + 1/R2
1/R = 1/14 + 1/72
1/R = 0.0853
R = 1/0.0853
R = 11.72
Total current in the circuit = V/R = 60/11.72 = 5.12 A
Current in 14 ohms = 60/14 = 4.29 A
Current in 72 ohms = 60/72 = 0.83 A
<h3>Power loss in each parallel resistor</h3>
P = IV
P(14 ohms) = (4.29) x 60 = 257.4 W
P(72 ohms) = 0.83 x 60 = 49.8 W
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