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SSSSS [86.1K]
3 years ago
13

A and B, move toward one another. Object A has twice the mass and half the speed of object B. Which of the following describes t

he forces the objects exert on each other when the collide and provides the best explanation? (A) The force exerted by A on B will be twice as great as the force exerted by B on A, as great as the force exerted by B on A other are the same, because the product of because A has twice the mass of B (B) The force exerted by A on B will be half because A has half the speed of B (C) The forces exerted by each object on the mass and speed is the same for both objects. (D) The forces exerted by each object on the other are the same, because inter objects cannot exert forces of difi magnitude on each other.
Physics
1 answer:
BARSIC [14]3 years ago
4 0

Answer:D

Explanation:

Given

mass of A is twice the mass of B half the velocity of B

Suppose F_a and F_b be the average force exerted on A and B respectively

and According to Newton third law of motion Force on the body A is equal to Force on body B but opposite in direction as they are action and reaction force.

Thus F_a=-F_b  and option d is correct

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False, that would be kinetic energy.

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Answer:

v=0.04m/s\\

s=-28.592m\\

Explanation:

a = 3t-4

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if t=3.6s and initial velocity, v0,  is -5m/s

v=0.04m/s\\

s(t)=\int\limits^t_0 {v(t)} \, dt =1/2*t^{3}-2t^{2}+v_0*t+s_0\\

if t=3.6s and the initial displacement, s0, is -8m:

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3 years ago
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4 years ago
A train traveling at 27.5 m/s accelerates to 42.4 m/s over 75.0 s. What is the displacement of the train in this time period
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Answer:

2621.25 meters

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Time = 75 seconds

We need to look at the kinematic equations and determine which one will be best.  In this case, we need an equation with distance.  I am going to use v_{f}^{2} = v_{i}^{2} +2ad, but you can also use the other equation, x = v_{o}t+\frac{1}{2}at^{2}

We need to find acceleration.  To find it, we need to use the formula for acceleration: a = \frac{v_{f}-v_{i}}{t}.  Plugging in values, a = \frac{42.4-27.5}{75} = .199\ m/s^{2}

Next, plug in what we know into the kinematics equation and solve for distance.  42.4^{2} = 27.5^{2} + 2(.199)(d)\\d = 2621.25\ meters

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