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2 years ago

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Need amswer fast plz

1 answer:

FrozenT [24]2 years ago

6 0

Answer:

I need this for may schooling

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A meter movement has a series resistance of 1Ω and a full scale current of 1mA. Use this meter movement to design a 10V full sca

Julli [10]

Answer:

10V = 1mA(1Ω + Rs)

Rs=10-1

Rs=9Ω

Explanation:

See the attached picture for diagram.

7 0

3 years ago

A race-car driver achiveved a speed of speed of m/s in 14 seconds after taking off from ready at the starting line . What was th

vladimir2022 [97]

Average acceleration = (change in speed) / (time for the change)

Average acceleration =

(speed at the end of the 14 seconds) / (14 seconds)

5 0

2 years ago

Sometimes when you are training for event you may notice a decrease in improvement in level out of performance true or false

blagie [28]

<span>Sometimes when you are training for event you may notice a decrease in improvement in level out of performance. T</span>rue

3 0

3 years ago

Read 2 more answers

An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a

devlian [24]

Answer:

a

$D = 1162.7 \ m$

b

$\beta =- 65.55^o$

Explanation:

From the question we are told that

The speed of the airplane is $u = 92.3 \ m/s$

The angle is $\theta = 51.1^o$

The altitude of the plane is $d = 532 \ m$

Generally the y-component of the airplanes velocity is

$u_y = v * sin (\theta )$

=> $u_y = 92.3 * sin ( 51.1 )$

=> $u_y = 71.83 \ m/s$

Generally the displacement traveled by the package in the vertical direction is

$d = (u_y)t + \frac{1}{2}(-g)t^2$

=> $-532 = 71.83 t + \frac{1}{2}(-9.8)t^2$

Here the negative sign for the distance show that the direction is along the negative y-axis

=> $4.9t^2 - 71.83t - 532 = 0$

Solving this using quadratic formula we obtain that

$t = 20.06 \ s$

Generally the x-component of the velocity is

$u_x = u * cos (\theta)$

=> $u_x = 92.3 * cos (51.1)$

=> $u_x = 57.96 \ m/s$

Generally the distance travel in the horizontal direction is

$D = u_x * t$

=> $D = 57.96 * 20.06$

=> $D = 1162.7 \ m$

Generally the angle of the velocity vector relative to the ground is mathematically represented as

$\beta = tan ^{-1}[\frac{v_y}{v_x } ]$

Here $v_y$ is the final velocity of the package along the vertical axis and this is mathematically represented as

$v_y = u_y - gt$

=> $v_y = 71.83 - 9.8 * 20.06$

=> $v_y = -130.05 \ m/s$

and v_x is the final velocity of the package which is equivalent to the initial velocity $u_x$

So

$\beta = tan ^{-1}[-130.05}{57.96 } ]$

$\beta =- 65.55^o$

The negative direction show that it is moving towards the south east direction

6 0

2 years ago

You have 50L of water, it froze. So find its new volume. Density of water is 1000kg/m^3 or 1kg/L, density of ice is 920kg/m^3 or

ad-work [718]

Answer:

D (density) = Mass / Volume

V (ice) = Mass / Density = 50000 g / .92 kg / L

V = 50 kg / .92 kg / L

1 Liter of water weighs 1 kilogram = 50 L weighs 50000 g

V = 54.3 L the mass does not change upon the change of phase (freezing)

4 0

2 years ago