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3 years ago

In the rectangle below, the two quarter circles are congruent. Find the area of the shaded of the shaded region.

Mathematics

1 answer:

Delicious77 [7]3 years ago

8 0

Rectangle:
length = 12
width = 6
area of rectangle = length times width = 12 x 6 = 72

area of circle = pi r^2 = 3.14 (6)^2 = 113.1
1/2 circle = 113.1 / 2 = 56.55

the area of the shaded of the shaded region = 72 - 56.55 = 15.45

answer
15.45

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Lunna [17]

Answer:

y = 1/2x -3

x=-2 ⇒ y = -4

x=-1 ⇒ y = -3.5

x=0 ⇒ y = -3

x=1 ⇒ y = -2.5

x=2 ⇒ y = -2

Step-by-step explanation:

Hi, to answer this question we have to isolate y:

x - 2y = 6

-2y =6-x

y = (6-x)/-2

y = -3+1/2x

y = 1/2x -3

Now, we have to create a table with the next values (see attachment)

x=-2 ⇒ y = 1/2x -3 = 1/2(-2)-3= -4

x=-1 ⇒ y = 1/2x -3 = 1/2(-1)-3= -3.5

x=0 ⇒ y = 1/2x -3 = 1/2(0)-3= -3

x=1 ⇒ y = 1/2x -3 = 1/2(1)-3= -2.5

x=2 ⇒ y = 1/2x -3 = 1/2(2)-3= -2

Feel free to ask for more if needed or if you did not understand something.

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4 years ago

Write an equation in slope intercept form of a line that passes through (-2, 1) and (4,2).

fenix001 [56]

Answer:

$\displaystyle y = \frac{1}{6}x + 1\frac{1}{3}$

Step-by-step explanation:

First, find the rate of change [slope]:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-1 + 2}{2 + 4} = \frac{1}{6}$

Now plug these coordinates into the Slope-Intercept Formula. It does not matter which ordered pair you choose:

2 = ⅙[4] + b

⅔

$\displaystyle 1\frac{1}{3} = b \\ \\ y = \frac{1}{6}x + 1\frac{1}{3}$

_______________________________________________

1 = ⅙[−2] + b

−⅓

$\displaystyle 1\frac{1}{3} = b \\ \\ y = \frac{1}{6}x + 1\frac{1}{3}$

** You see? I told you it did not matter which ordered pair you choose because you will ALWAYS get the exact same result.

I am joyous to assist you anytime.

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3 years ago

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Yuri [45]

Answer:

$92.55

Step-by-step explanation:

Substitute the value of x, which is in weeks, to 12.

so y = 0.91(12) + 103.47

y = 92.55

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Answer:

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Step-by-step explanation:

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