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DochEvi [55]
3 years ago
13

If DF = 9x-39, find EF.

Mathematics
1 answer:
otez555 [7]3 years ago
7 0

DF=DE+EF\\\\DF=9x-39\\DE=47\\EF=3x+10\\\\\text{substitute}\\\\9x-39=47+3x+10\\9x-39=3x+57\ \ \ |-3x\\6x-39=57\ \ \ \ |+39\\6x=96\ \ \ \ |:6\\x=16\\\\\text{put the value of x to the expression}\ 3x+10\\\\EF=3(16)+10=48+10=58

Answer: EF = 58

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I know the answer is C. but I need to know how to solve it!
otez555 [7]
Yes you are right it's C)
Notice  that f(-2) = (-2)³ +2( - 2)² + 4(-2) + 8 =0
Then x³+2x²+4x+8 is divisible by (x+2)
Perform this division & you will get:

x³+2x²+4x+8 = (x+2)(x²+4)
 The root of (x+2) is the value that render it nil, that is x=-2
  The root of (x²+4) are imaginary (not real) because
  x²+4 =0 ==> x² = -4 & x=√-4 or x= 2i (nor real).
Hope you understood the reasoning



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3 years ago
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