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3 years ago

If DF = 9x-39, find EF.

Mathematics

1 answer:

otez555 [7]3 years ago

7 0

$DF=DE+EF\\\\DF=9x-39\\DE=47\\EF=3x+10\\\\\text{substitute}\\\\9x-39=47+3x+10\\9x-39=3x+57\ \ \ |-3x\\6x-39=57\ \ \ \ |+39\\6x=96\ \ \ \ |:6\\x=16\\\\\text{put the value of x to the expression}\ 3x+10\\\\EF=3(16)+10=48+10=58$

Answer: EF = 58

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Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12

Montano1993 [528]

$0.05p-0.02(5-2p)=0.05(p-2)-0.12$

$0.05p-0.02(5-2p)=0.05(p-2)-0.12:p$

$
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$0.09p-0.1=0.05p-0.1-0.12
 
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$0.09p-0.1=0.05p-0.22$

$
0.09p-0.1-0.05p=-0.22
 

$ $|Subtract \ 0.05p \ from \ both \ sides|$

$
0.04p-0.1=-0.22
 
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$
0.04p=-0.22+0.1
 
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8 0

3 years ago

Would the answer be b an d for this

Paladinen [302]

Answer by answer key by key question equals equation

3 0

3 years ago

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What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

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3 years ago

Raman purchased 2 an 1/2 pounds of chocolate covered peanuts for $9.75. WHat was the price per pound

viktelen [127]

Answer:

$3.9 per pound

Step-by-step explanation:

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2 years ago

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100% pure gold is 24 karat gold, which is too soft to be made into jewelry most call Jory is 14 karat gold proximally 58% gold 1

denis-greek [22]

Answer:

The amount of gold used in a 200 g 14 gold bracelet is 116 g.

Step-by-step explanation:

Since a 14 karat jewell is stated to have aproximally 58 % of it's weigh in gold we need to take the total weigh of the jewel in question and find that percentage of it's weigh. In order to find that percentage we'll first convert that number into a decimal, we do that by dividing it by 100, so we have 58% = 58/100 = 0.58 we can multiply this value by the weigh of the jewel to find the amount of gold used. So we have:

gold used = total weigh*0.58 = 200*0.58 = 116 g

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