Answer:
Step-by-step explanation:
Answer: 3x^3 - 3x^2 - 4x - 4
Explanation:
(x - 2)(3x^2 + 3x + 2)
= x(3x^2 + 3x + 2) - 2(3x^2 + 3x + 2)
= 3x^3 + 3x^2 + 2x - 6x^2 - 6x - 4
= 3x^3 - 3x^2 - 4x - 4
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Simply divide 61.50 by 3. You should be able to reach the answer that way
