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Pachacha [2.7K]
2 years ago
11

Which function has a domain of all real numbers except x=pi/2+-npi?

Mathematics
2 answers:
OLga [1]2 years ago
8 0
It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.
lord [1]2 years ago
7 0

Answer:

y=secx

Step-by-step explanation:

A p e x T r i g o n o m e t r y

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Ulleksa [173]
You do it be dividing the numerator and denominator by the same number, but you have to make sure the divide into whole numbers

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2 years ago
What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
IrinaK [193]
Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)

We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):

Thus,

Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

Therefore, 

log of 1/2 (w^4 u^2 / v^3)

and for the final step and answer, reorder or rearrange w^4 and u^2:

log of 1/2 (u^2 w^4 / v^3)  
8 0
3 years ago
Read 2 more answers
Give the equation for a circle with the given center and radius.Center at (-10, -4), radius = 5A. (x−10)^2+(y−4)^2=25B. (x−4)^2+
BaLLatris [955]

D)(x+10)^2+(y+4)^2=5^2=25

Explanation

Step 1

We know that the general equation for a circle is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\  \end{gathered}

where

(h,k) is the center of the circel

and r is the radius

then, all we need to do is replace

Let

\begin{gathered} \text{center}\Rightarrow(h,k)\Rightarrow(-10,-4) \\ \text{radius}\Rightarrow r\Rightarrow5 \end{gathered}

replace the values

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-(-10))^2+(y-(-4))^2=5^2 \\ (x+10)^2+(y+4)^2=5^2=25 \end{gathered}

therefore, the answer is

D)(x+10)^2+(y+4)^2=5^2=25

I hope this helps you

7 0
1 year ago
What is the the value of ∣9∣
xxTIMURxx [149]

Hey there! I'm happy to help!

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Have a wonderful day and keep on learning! :D

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2 years ago
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TEA [102]

It is the graph where the two lines intersect, when they intersect there is a point where they connect, and that is your answer

3 0
3 years ago
Read 2 more answers
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