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Pachacha [2.7K]

3 years ago

11

Which function has a domain of all real numbers except x=pi/2+-npi?

2 answers:

OLga [1]3 years ago

8 0

It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.

lord [1]3 years ago

7 0

Answer:

y=secx

Step-by-step explanation:

A p e x T r i g o n o m e t r y

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Answer:

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Strike441 [17]

Step-by-step explanation:

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OleMash [197]

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The side lengths of a triangle are 9, 12, and 15. Is this a right triangle?

andriy [413]

Answer:

<h2>Yes, this is a right triangle.</h2>

Step-by-step explanation:

Hypotenuse always have the highest number than base and perpendicular.

Hypotenuse ( h ) = 15

Base ( b ) = 9

Perpendicular ( p ) = 12

Let's see whether the given triangle is a right triangle or not

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

Plugging the values,

${15}^{2} = {12}^{2} + {9}^{2}$

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Hypotenuse is equal to the sum of perpendicular and base.

So , we can say that the given lengths of the triangle makes a right triangle.

Hope this helps..

Best regards!!

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