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Pachacha [2.7K]

3 years ago

11

Which function has a domain of all real numbers except x=pi/2+-npi?

2 answers:

OLga [1]3 years ago

8 0

It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.

lord [1]3 years ago

7 0

Answer:

y=secx

Step-by-step explanation:

A p e x T r i g o n o m e t r y

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A florist has 30 carnations and 42 roses. He wants to put the flowers in vases so that each vase has the same number of flowers

Nesterboy [21]

Note that

30=2·3·5;
42=2·3·7.

Find the grearest common factor GCF(30,42). You can see that numbers 30 and 42 have common factors 2 and 3, then

$GCF(30,42)=2\cdot 3=6.$

This gives that the greatest number of identical vases florist can fill is 6. Each vase will contain

$30:6=5$ carnations;
$42:6=7$ roses.

Therefore, in each vase will be 12 flowers (5 carnations and 7 roses).

4 0

3 years ago

which of the points (s,t) is inside the shaded region of the set of inequalities qualities shown below?

gogolik [260]

Answer:

Step-by-step explanation:

A looks good

5 0

3 years ago

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dem82 [27]

Answer:

$\huge\boxed{9}$

Step-by-step explanation:

$\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}$

Rule of exponents $a^0 = 1$ , $1/a^m = a^{-m}$

=> $\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}$

=> $\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}$

Combining same bases

=> $\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}$

When bases are same , powers are to be added

=> $\sf 2 ^{-16-12+28} * 3^{10-8}$

=> $\sf 2^{-28+28} * 3^2$

=> $\sf 2^0 * 3^2$

=> $\sf 3^2$

=> 9

8 0

3 years ago

Alice earns 1.5 times her normal hourly rate for each hour she works after 40 hours .she worked 50 hours this week and earned 66

Tcecarenko [31]

660 divided by 2 and it gives you your answer of 13.2
So therefore the answer is 13.2 per hour

8 0

3 years ago

Compute the probability of the event E1 that Bob wins in a duel against Eve alone, assuming he shoots first. (Hint: Let x be the

skad [1K]

Answer: Hello your question is incomplete attached below is the missing

n ( 1 + n )

Step-by-step explanation:

P( Bob hits target ) = 1/3

P( Eve hits target ) = 2/3

P( Carol hits target ) = 1

<u>Compute the P that Bob wins in a duel against Eve alone</u>

P(Bob hits the target in first shot ) = n = 1/3

P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9

hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )

6 0

3 years ago