Answer:
Step-by-step explanation:
First it base times height times (1/2)
The base is 7 boxes
The height is 5 boxes
A=(7)(5)(1/2)
A=(35)(1/2)
A=17.5
Answer:
1 1/2
Step-by-step explanation:
3^3/7 ≈ 1.601
1.601 rounded to the nearest half is 1 1/2.
Hello!
The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.
First, let's find the y-intercept. This is where the line hits the y-axis. Therefore, it hits at 4 on the y-axis, so our y-intercept is 4.
To find the slope, let's find 2 points on our line. Let's use (0,4) and (2,5). We divide the difference in the y-values by the difference in the x-values as shown below.

Therefore, our slope is 2.
Now we plug these values into our equation.
y=2x+4
I hope this helps!
Answer:
-243
Step-by-step explanation:

Answer:
a.No
b.No
c.No
Step-by-step explanation:
a.No,Such set does not exist .A set of natural numbers is N
Every point of this set is an isolated point but no accumulation point
Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself

Interior point of set :Let
.Then a is called interior point of set when its neighborhood is a subset of set S.

When a set is uncountable then interior point exist it is necessary for interior points existance .
Boundary points :Let
.If every non empty neighborhood of a intersect S and complement of S.
Every member of a set is a boundary point
b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers
c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point