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4 years ago

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Tracy has 5 cans of vegetable juice in her refrigerator. Four of the cans each have 6 ounces of juice. Write an expression for t

he total ounces of juice Tracy has in her refrigerator. if the fifth can has 12 ounces, what's the total ounces of juice Tracy has?

1 answer:

mojhsa [17]4 years ago

8 0

Answer:

4(6)+12=36

Step-by-step explanation:

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A large concrete block is used for the cornerstone

marin [14]

Answer:

The volume of the concrete needed to make the block is 5054 ft³

Step-by-step explanation:

The question relate to the calculation of the volume of a shape

The dimensions of the block are;

The depth of the block, d = 19 ft.

The width of the block, w = 19 ft.

The length of the block, l = 14 ft.

The volume of a cube, V = Length, l × Width, w × Depth, d

Therefore, the volume, 'V' of a cubic block is given as follows;

V = l × w × d = 14 ft. × 19 ft. × 19 ft. = 5054 ft.³

The volume of the concrete needed to make the block = The volume of the block, V = 5054 ft³.

8 0

3 years ago

A local pizzeria offers 11 toppings for their pizzas and you can choose any 4 of them for one fixed price. How many different ty

choli [55]

First slot, 11 options
2nd is 10 (1 less than 1st slot)
3rd is 9
4th is 8

11*10*9*8=7920 different pizzas (assuming you can't order all 1 topping)

5 0

3 years ago

Write an equation for the graph below in terms of x

finlep [7]

Answer:

x = -2

Step-by-step explanation:

the line goes through -2 on the x-axis

the line also goes through -3 on the y-axis

4 0

3 years ago

Find the domain and range of the function below

natali 33 [55]

X is greater than or equal to 0
y is greater than or equal to 0

6 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago