Question

to function properly, rainwater outflow pipe must drop exactly 1 inch for every 25 inches of horizontal distance. A 40 foot long rain water pipe runs under the edge of a roof. What is the vertical distance, in inches, the pipe bust drop between its ends? Round your number to the nearest tenth.

Answer 1

40 ft x 12 to convert it to inches.
480 inches / 25 inches = 19.2 Inches dropped.

Answer 2

Answer: Hence, There is vertical distance of 19 inches the pipe must drop between its ends.

Step-by-step explanation:

Since we have given that

Rainwater outflow pipe must drop exactly 1 inch for every 25 inches of horizontal distance.

For 1 inch = 25 inches of vertical distance the pipe must drop.

If there is a 40 foot long rain water pipe runs under the edge of a roof.

Then, we need to find the vertical distance in inches the pope must drop.

First, we change 40 feet into inches.

Since 1 foot = 12 inches

40 feet = 40×12 inches = 480 inches

So, Vertical distance the pipe must drop is given by

$\dfrac{480}{25}\\\\=19.2\ inches$

Hence, There is vertical distance of 19.2 inches ≈ 19 inches the pipe must drop between its ends.