The mean of a distribution is the sum of the data elements divided by the count of the dataset.
<em>The mean of the distribution is 4</em>
The complete table is given as
![\left[\begin{array}{cc}People & Frequency &0 - 2 & 5 & 3 - 5 & 25 & 6 - 8 & 5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DPeople%20%26%20Frequency%20%260%20-%202%20%26%205%20%26%203%20-%205%20%26%2025%20%26%206%20-%208%20%26%205%5Cend%7Barray%7D%5Cright%5D)
The complete question requires that, we calculate the mean of the dataset
First, we calculate the class midpoint
This is the average of the class interval
<u />
<u>For interval 0 - 2, </u>
<u>For interval 3 - 5,</u>
<u>For interval 6 - 8</u>
So, the table becomes
![\left[\begin{array}{ccc}People & x & Frequency &0 - 2 &1 & 5 & 3 - 5 & 4& 25 & 6 - 8& 7 & 5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DPeople%20%26%20x%20%26%20Frequency%20%260%20-%202%20%261%20%26%205%20%26%203%20-%205%20%26%204%26%2025%20%26%206%20-%208%26%207%20%26%205%5Cend%7Barray%7D%5Cright%5D)
The mean is then calculated as:
This gives
Hence, the mean of the distribution is 4
Read more about mean at:
brainly.com/question/17060266
Answer: 170.37 acres
Step-by-step explanation:
In 2005, x= 2005
Substituting x=2005 in the equation.
A(2005) = (2078x-94458)/(13x-2164)
A(2005) = 4071932/23901
A(2005) = 170.37 acres
The opposite of -48 is positive 48, Written as just 48.
Answer:
Part A
C = $.85p
For 2 pounds , the charge is $1.70
Part B
C = $.05 * p
Step-by-step explanation:
Part A
Cost = charge per pound * pounds
We know the charge per pound is $.85
C = $.85 * p
We want to ship 2 pounds
C = .85*2
C = 1.70
Part B
Cost = charge per pound * pounds
We know the charge per pound is now $.05
C = $.05 * p
I'm not 100% sur what it is asking but I think the expression would be
15 min. * 10 = min. till the tank is full
