Simplify (2^8*3^-5*6^0)^-2 * (3^-2\2^3)-^4 * 2^28=
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Answer:
The average velocity of the ball at the given time interval is -122.3 ft/s
Step-by-step explanation:
Given;
velocity of the ball, v = 34 ft/s
height of the ball, y = 34t - 26t²
initial time, t₀ = 3 seconds
final time, t = 3 + 0.01 = 3.01 seconds
At t = 3 s
y(3) = 34(3) - 26(3)² = -132
The average velocity of the ball in ft/s is given as;
Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s
Step-by-step explanation:
Here, we'll need to multiply these two values together. I'll use the expansion formula, which goes as follows:
- Expand
Lets apply this to the following equation:
- Expand.
- Simplify.
- Remove parenthesis and add.
Answer:
x^2+10x+21