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4 years ago

Y= -5x-10 y=6x+12 solve by substitution

Mathematics

2 answers:

Mamont248 [21]4 years ago

4 0

Answer:

(-2,0) x=-2 y=0

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation

Hope this helps!

jasenka [17]4 years ago

4 0

Answer:

Step-by-step explanation:

y+10=−5x

− 5 y+10 =x

x=− 5 y+10

----------------

y−12=6x

y−12 /6=x

x= y−12 /6

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There are between 24 and 40 students in the class.

riadik2000 [5.3K]

Answer:

There are 22 or 33 students

Step-by-step explanation:

8 0

4 years ago

What is the value of e^3x+6=8

Natasha2012 [34]

Hello there!

Answer: ⇒⇒ $x=\frac{2}{e^3}$

___________________________________________________

Step-by-step explanation:

First you had to subtract by 6 from both sides of equation.

$e^3x+6-6=8-6$

Simplify.

$e^3x=2$

Then you divide by e³ from both sides of equation.

$\frac{e^3x}{e^3}=\frac{2}{e^3}$

Simplify it should be the correct answer.

$x=\frac{2}{e^3}$

____________________________________________________________

Hope this helps!

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Have a great day!

-Charlie

4 0

3 years ago

A. 312 b. 317 c. 315 d. 316

Soloha48 [4]

Answer:

B.) 317

Step-by-step explanation:

100/2 = 50

124/2 = 62

180/2 = 90

634/2 = 317

5 0

3 years ago

Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student

SashulF [63]

Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

Verify the midpoint of each student

student 1

we have the endpoints

(-9,0) and (11,-8)

substitute in the formula

$M(\frac{-9+11}{2},\frac{0-8}{2})$

$M(1,-4)$

The midpoint is not (-1,4)

student 2

we have the endpoints

(-6,-1) and (4,-7)

substitute in the formula

$M(\frac{-6+4}{2},\frac{-1-7}{2})$

$M(-1,-4)$

The midpoint is not (-1,4)

student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

$M(\frac{-5+3}{2},\frac{2+6}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

$M(\frac{-3+5}{2},\frac{10-2}{2})$

$M(1,4)$

The midpoint is not (-1,4)

student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

$M(\frac{0-2}{2},\frac{-3+11}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

therefore

Student 3 and student 5

3 0

4 years ago

Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is viable solutio

madam [21]

Let's say the number of days library book is late is X, and the total fee is Y.

Liability charges $0.30 dollars as a fee for being 1 day late,

For being 1 day late, fee charge is: 1* $0.30

So, for X days the charge would be: X*$0.30.

Total charge for being X days late is Y, Which means: Y= 0.30 * X.

Now We would have to check all the viable solutions in the answer to see if they satisfy the equation Y= 0.30 * X

Option one(-3, -0.9) and two (-2.5, -0.75) Would not be a viable solution because the value of number of days can not be negative and in option one and two, value of days -3 and -2.5 is negative.

Option three(4.5, 1.35) can not be correct because library charges fee for a full day so the number for days would be a whole number. Library would not charge for 4.5 days, they would either charge of 4 days or 5 days because 4.5 is not an whole number.

Option four(8, 2.40) is the correct answer because it satisfies our equation;

Y= 0.30 * X

2.40= 0.30 * 8

2.40 = 2.40.

Fourth option (8, 2.40) is the only viable solution to this question.

Read more on Brainly.com - brainly.com/question/359512#readmore

8 0

3 years ago