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3 years ago

Please help me on this

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

Answer: Option A.

Step-by-step explanation:

The angle ∠QST and the angle ∠QSR are supplementary.

If two angles are supplementary, means that the sum of both angles is 180 degrees.

Thenrefore

$QST+QSR=180\°$

Solve for the angle ∠QSR and substitute the value of the angle ∠QST to find the value of the angle ∠QSR. Then, solving the equation, you get:

$QSR=180\°-QST\\QSR=180\°-150\°\\\\QSR=30\°$

Then $tan(QSR)$ is:

$tan(30\°)=\frac{\sqrt{3}}{3}$

This matches with the option A.

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To do this, you need to look on the graph and it's not hard from there.

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3 years ago

How many two-digit numbers are there in which the tens digit is greater than<br> the ones digit?

Dovator [93]

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

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1 year ago

14 pies eaten in 2 minutes what's the rate

anyanavicka [17]

Answer:

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Step-by-step explanation:

14/2 =7

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3 years ago

Read 2 more answers

An AISI 1040 cold-drawn steel tube has an OD 5 50 mm and wall thickness 6 mm. What maximum external pressure can this tube withs

lukranit [14]

Answer:

82.79MPa

Step-by-step explanation:

Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa

Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,

Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)

The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))

But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ

σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)

p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.

Hope this helps!!

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3 years ago

The table shows a bicycle rider moving at a constant rate of speed.

Mariana [72]

<h2><u>Answer:</u></h2><h2> $\boxed{\boxed{\sf{Distance}}}$ </h2><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Dependent Variable:</h3>

A dependent variable is almost always the $(y)$ variable. This also means it depends on another variable. The way you can tell it's dependent for this problem is that the per the rule: distance = time. This means that the distance changes based on the time.
$(y)$ depends on $(x)$

So your answer is Distance.

______________________________

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2 years ago