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2 years ago

Carl types 180 words in 2 minutes. What is the number of words Carl types in 5 minutes?

Mathematics

2 answers:

LekaFEV [45]2 years ago

6 0

450

180 / 2 = 90

90 x 5 = 450

cestrela7 [59]2 years ago

5 0

180 words in 2 minutes

x words in 5 minutes

2x= 180*5

2x= 900

x= 900/2

x= 450

Answer : Carl types 450 words in 5 minutes

I hope that's help !

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Express 1/10 cm as a fraction of 3 metres

Liula [17]

Answer:

1/3000

Step-by-step explanation:

3 meters to centimeters:

3 × 100 = 300

= 1/10 ÷ 300

= 1/10/300

= 1/(10×300)

= 1/3000

7 0

2 years ago

If y varies directly with x. and y=10 when x=5.6, find the value of y when<br> X=3

Nady [450]

Answer: 5.3571

Step-by-step explanation:

The formula used to calculate direct proportion is: y = kx

We will find the constant of proportionality when y=10 and x=5.6. This will be:

y = kx

10 = 5.6k

k = 10/5.6

k = 1.7857143

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3 0

2 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

9 months ago

Can someone help me????

SpyIntel [72]

Lemme think bout it....no

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2 years ago

Why does multiplying by 10 shift each digit one place to the left?

Leto [7]

as we move down the list as we push the *digits* to the *left*through the decimal *point* *each* *number has been 10*. and so we can easily *multiply* or divide by *a* power of *10* because of our system of positional numeration. Each Place belongs to the next power of *10*.

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2 years ago