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3 years ago

The vertices of a triangle are A (0,0), B (3, 4) and C (-4,5). Find the length of each side.

Mathematics

1 answer:

Sphinxa [80]3 years ago

7 0

Answer:

AB = 5 units

BC = 5 $\sqrt{2}$ units

AC = $\sqrt{41}$ or about 6.4 units

Step-by-step explanation:

distance formula: square root of the sum of the difference of the y-values and the difference of the x-values

ex, dAB = √(4-0)² + (3-0)²

= √16 + 9

= √25

= 5

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The vertices of a triangle are A (0,0), B (3, 4) and C (-4,5). Find the length of each side. ​

The vertices of a triangle are A (0,0), B (3, 4) and C (-4,5). Find the length of each side.