Question

The vertices of a triangle are A (0,0), B (3, 4) and C (-4,5). Find the length of each side. ​

Answer 1

Answer:

AB = 5 units

BC = 5$\sqrt{2}$ units

AC = $\sqrt{41}$ or about 6.4 units

Step-by-step explanation:

distance formula:  square root of the sum of the difference of the y-values and the difference of the x-values

ex, dAB = √(4-0)² + (3-0)²

              = √16 + 9

              = √25

              = 5