Plot the following points: A (-2, 2) B (-4,-4) C(1,-4) D (3, 2) Connect the points. What is the name of the polygon? How long is
line segment AD? What is the area of the shape?
1 answer:
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According to the given table, the slope-intercept equation of the line is given by:
The equation of a line, in <em>slope-intercept</em> form, is given by:
In which:
- The slope is m.
- The intercept is b.
In this problem, we are given two points, (3,-5) and (-2,5).
- The slope is given by <u>change in y divided by change in x</u>, hence:
Hence:
Point (3,-5) means that when , which is used to find b.
Hence, the equation of the line is:
A similar problem is given at brainly.com/question/24685547
Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
