Answer:
Step-by-step explanation:
Angle g would be congruent/equal to itself because of verticals angles theorem. i hope that helped a bit
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
x = 90°
3x = 270°
Step-by-step explanation:
Split the shape in half through the plane of 3x and x.
We can find the angle of x/2 is 45°.
Since x/2 = 45°, then we can fid that x=90°.
To find 3x, we simply multiply 90° 3 times.
So 3x = 270°.
