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melamori03 [73]
3 years ago
14

Draw a model to represent the ratio 1 to 3. Describe how to use the model to find an equivalent ratio. Please help I'm really st

uck.
Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer: See below

Step-by-step explanation:

Make a table with first set of numbers as 1,3. Multiply both the numbers of this set sequentially by natural numbers to get the following table

1   2  3  4    5    6     7    8     9      10......

3  6  9  12  15    18   21   24   27    30......

We see that in each set of numbers the 2nd number is 3 times the first number.

If we plot these sets of numbers on a graph paper, we get a model depicting all the points which satisfy this ration requirement.

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The answer should be 132 degrees.

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Answer: $1040

A = P + I

A = Total

P = Principal

I = Interest

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

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