The answer would be b. 3/5 because if heads takes up 2 out of 5, the three left have to be tails.
Step-by-step explanation:
If 3 HD and 2HB cost $7.50
2 HD and 3HB cost $8.75
Let,y be HD
Y be HB
So 3y + 2x = $7.50. Eqn 1
2y + 3x = $8.75. Eqn 2
Solve simultaneously
Make x the subject in Eqn 1
3y + 2x = 7.50
2x = 7.50 - 3y
Devide by the coefficient of x
2x/2 = (7.50 - 3y) / 2
X = (7.50 - 3y) /2 Eqn 3
Put Eqn 3 into 2
2y + 3(7.50 - 3y) / 2 = 8.75
2y (22.5 - 9y) / 2 =8. 75
Multiply by the lcm of the denominators
2y x 2 + ((22.5 - 9) / 2) x 2 = 8.75 x2
4y + 22.5 - 9y = 17.50
Group like terms
22.5 - 17.50 = 9y - 4y
5 = 5y
5/5 = (5y) / 5
1 = y Eqn 4
Therefore 1 HD is $1
Put Eqn 4 into eqn 3
X = (7. 50 - 3y) / 2
X = (7.50 - 3(1)) / 2
X = 4.5 / 2
X = 2.25
Therefore 1 HB is $2.25
Answer: "Subtract 6 from both sides, and then divide by 2. The solution is x = 8"
Step-by-step explanation: Lets solve for 2x + 6 = 22
Step 1 Subtract 6 from both sides: 2x + 6 - 6 = 22 - 6 2x = 16
Step 2 Divide by 2 in both sides: 2x/2 = 16/2
Step 3 The answer: x = 8
Let length be (l) and width be (w).
According to the question, l=3w+3......equation1
And perimeter that is 2(l+w) =94........equation2
Solve these two equations, you get your answer.
l=36
w=11
Answer:
x=3,y=7
Step-by-step explanation:
8x+3y=45
2x+3y=27
8x-2x=6x
45-27=18
<u>6</u><u>x</u><u>=</u><u>1</u><u>8</u>
6. 6
x=3
2x+3y=27
2(3)+3y=27
6+3y=27
3y=27-6
<u>3</u><u>y</u> = <u>2</u><u>1</u>
3. 3
y=7