HELP PLEASE 9TH GRADE MATH
1 answer:
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Answer:
d = -1/3, 0
Step-by-step explanation:
Subtract the constant on the left, take the square root, and solve from there.
(6d +1)^2 + 12 = 13 . . . . given
(6d +1)^2 = 1 . . . . . . . . . .subtract 12
6d +1 = ±√1 . . . . . . . . . . take the square root
6d = -1 ±1 . . . . . . . . . . . .subtract 1
d = (-1 ±1)/6 . . . . . . . . . . divide by 6
d = -1/3, 0
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Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:
f(x) = (6x+1)^ +12 -13
We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.
Answer:
<C=26
<B=48
<D=106
<F=42
Step-by-step explanation:
I labeled all the angles to help this make more sense :)
So first we find <C, which is supplementary to <E so just do 180-154=26
Next, we know that <F and <B are equal because they form corresponding angles.
Angles <C <D and <B form a triangle. The three angles of a triangle always equal 180. Now that we know angles <C and <B, we just do 180-26-48=106.
Lastly, to find angle A, we just take 180-106-48=42.
Hope this helps
