3 years ago

1.5 more than the quation of a and 4 is b

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

A/4 + 1.5 = b
hope it helps

You might be interested in

0.2(x + 1) + 0.5x = -0.3(x - 4)?

andreyandreev [35.5K]

Answer:

x=1.....................

7 0

3 years ago

Thanks if u can do all of these for me!!! I need the work and the answers thank u!!;)

noname [10]

Tha number one the aswer is b 5.4

6 0

3 years ago

Read 2 more answers

To convert 4.1 kilometers to meters ,you would use the ratio 1,000meters/1 kilometer

boyakko [2]

4,100 meters. Hope it helped

7 0

4 years ago

- 7 ( z - 6 ) = - 70

NemiM [27]

Answer:

z=16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−7(z−6)=−70

(−7)(z)+(−7)(−6)=−70(Distribute)

−7z+42=−70

Step 2: Subtract 42 from both sides.

−7z+42−42=−70−42

−7z=−112

Step 3: Divide both sides by -7.

−7z /−7 = −112 /−7

z=16

7 0

3 years ago

Read 2 more answers

The first aircraft has 51 more seats than the second aircraft. the third aircraft has 54 fewer seats than the second aircraft. i

NikAS [45]

Let a = aircraft 1 seats

Let b = aircraft 2 seats

Let c = aircraft 3 seats

From the information given above, let's make basic equations.

$a=51+b$

$b=b$

$c=b-54$

$a+b+c=411$

We can begin to plug in values we know.

$51+b+b+b-54=411$

$3b-3=411$

$3b=414$

$b=138$

We now know that the second aircraft has 138 seats. Now we can plug in this value to find the value of the other seats. Let's start with the first aircraft.

$a=51+b$

$a=51+138$

$a=189$

We now know that the first aircraft has 189 seats. Let's now finally solve for the third aircraft.

$c=b-54$

$c=138-54$

$c=84$

Finally, we know that aircraft 3 has 84 seats. To check our work, let's make sure that each of these values add up to 411.

$a+b+c=411$

$189+138+84=411$

$411=411$

This is true, therefore the values are correct.

Aircraft 1: 189 seats

Aircraft 2: 138 seats

Aircraft 3: 84 seats

4 0

3 years ago