Answer:
616
Step-by-step explanation:
The equation to find the area of a trapezoid is: A = ½ (b
+b²) h.
b1=43
b2=45
h=14
Plug the variables in and solve.
![A=\frac{1}{2} (43+45)14](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%2843%2B45%2914)
![A=\frac{1}{2} (88)14](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%2888%2914)
![A=\frac{1}{2} (1232)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%281232%29)
![A=616](https://tex.z-dn.net/?f=A%3D616)
Answer:
t=7,t=0
Step-by-step explanation:
2t^2-14t+3=3
Subtract 3 from both sides
2t^2 - 14t +3 - 3 = 3-3
Simpilfy
2t^2 -14t = 0
Answer:
7.87 years
Step-by-step explanation:
#First we determine the effective annual rate based on the 9% compounded semi annual;
![i_m=(1+i/m)^m-1\\\\=(1+0.09/2)^2-1\\\\=0.09203](https://tex.z-dn.net/?f=i_m%3D%281%2Bi%2Fm%29%5Em-1%5C%5C%5C%5C%3D%281%2B0.09%2F2%29%5E2-1%5C%5C%5C%5C%3D0.09203)
#We then use this effective rate in the compound interest formula to solve for n. Given that the principal doubles after 2 yrs:
![A=P(1+i)^n\\\\A=2P, i=i_m\\\\16000=8000(1.09203)^n\\\\2=1.09203^n\\\\n=\frac{log \ 2}{log \ 1.09203}\\\\=7.87324\approx7.87 \ yrs](https://tex.z-dn.net/?f=A%3DP%281%2Bi%29%5En%5C%5C%5C%5CA%3D2P%2C%20i%3Di_m%5C%5C%5C%5C16000%3D8000%281.09203%29%5En%5C%5C%5C%5C2%3D1.09203%5En%5C%5C%5C%5Cn%3D%5Cfrac%7Blog%20%5C%202%7D%7Blog%20%5C%201.09203%7D%5C%5C%5C%5C%3D7.87324%5Capprox7.87%20%5C%20yrs)
Hence, it takes 7.87 years for the principal amount to double.
Answer:
C. 30
Step-by-step explanation:
-It is a statistical rule of thumb that the size of a sample must be
.
-This size is deemed adequate for the Central Limit Theorem to hold.
-At this size or greater, the shape of the resultant distribution is normal.
#It should however be noted, that for a normal distribution the CLT holds even for smaller sample sizes.