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2 years ago

Mrs. Sheppard is teaching a 5th grade class. She is standing 15 feet in front of Shawna.

Mathematics

1 answer:

tino4ka555 [31]2 years ago

4 0

Answer:

1-2 ft apart because the radius angle would be 2ft since its not a straight forward lining its horizontal.

Step-by-step explanation:

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If figure 1 has 4 tiles, fig 2 has 10, and fig 3 has 16... What is my rule?

Sever21 [200]

Answer:

Add 6 each time.

Step-by-step explanation:

Figure 1 has 4 tiles.

To go from figure 1 (4 tiles) to figure 2 (10 tiles), you added 6 tiles.

To go from figure 2 (10 tiles) to figure 3 (16 tiles), you added 6 tiles.

∴ the rule is to add 6 tiles each time.

7 0

3 years ago

Write the equation of the line passing through the points (2,-5) and (7,-3).

Grace [21]

Answer:

5y·2x=21

Step-by-step explanation:

using the formula above,you will find the equation 5y–2x=21

7 0

3 years ago

A sidewalk around a circular park covers a distance of 65 meters. A new sidewalk is being constructed across the park through it

Tpy6a [65]

Answer:

102

Step-by-step explanation:

6 0

3 years ago

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Evalute this integral

enot [183]

Answer:

(1/2)sin(2x) + C

Step-by-step explanation:

$y=2x\\\frac{dy}{dx} =2\\\ dx=\frac{dy}{2} \\\int\limits {cos 2x} \, dx \\\int\limits {cos(y) } \, \frac{dy}{2} =\frac{1}{2} \\\int\limits {cos(y) } \, dy=\frac{1}{2}sin(y) \\ substitute / y=2x\\\int\limits {cos 2x} \, dx = \frac{1}{2}sin(2x) +C$

4 0

3 years ago

Find the gradient of the line segment between the points (4,3) and (5,6).

vesna_86 [32]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. \space What is Asked}}$

Find the gradient of the line segment between the points $\bf{(4,3)\:and\:(5,6)}$

$\Large\maltese\underline{\textsf{B. This problem has been solved!}}$

The formula used, here is

$\bf{m=\dfrac{y2-y1}{x2-x1}$

$\cline{1-2}$

Now let's put in the co-ordinates from these two points.

$\bf{m=\dfrac{6-3}{5-4}}$ | subtract on top & bottom

$\bf{m=\dfrac{3}{1}}$ | divide

$\bf{m=3}$

$\cline{1-2}$

$\bf{Result:}$

$\bf{=m=3}$

$\boxed{\bf{ aesthetic\not101}}$

3 0

2 years ago

Read 2 more answers