Question

Can someone help me with these? Will give brainliest

Answer 1

One and Two
The vertices + faces  - edges = 2
 14 + f - 36
f - 22 = 2
f = 22 + 2 = 24

You have that right. So is the next one.

Four
I can find the surface area
Area = 2*triangles +   height * hypotenuse +( one smaller side + other smaller side)* height
Area = 2*(1/2 * 6*9) + 10.82 *25 + (6 + 9)*25
Area = 54 + 255.25 + 15*25
Area = 54 +270.5 + 375
Area = 698.25 I see that I could have made that shorter.
Area = 698

I have no idea how you would choose to do the lateral area, I can guess. For this question you take the perimeter of the 9 width and 25 length and multiply by the height 6.
6*(68) = 408 but that's wrong.

Try the triangle
Perimeter of the triangle = 6 + 9 + 10.82 = 25.82 
Now multiply by the height = P * h
Lateral Area = 25.82 * 25 = 645.5 That appears in the first answer, but not in the  last.

there's only one more to try. Perimeter of the 6 base 2*L + 2*W
2*6 + 2*25 = 62
Then multiplied by the height (9)
62*9 = 558 and that's not right. Sorry I can't give you an answer for this. Check my numbers.

Try D <<<<< answer

Five
SA = 2 * lids + can surface
SA = 2 * pi * r^2 + Circumference * height
SA = 2 * pi * 36 + 2*pi * r * 12
SA = 72*pi + 144 pi
SA = 216 in^2

A <<<<< answer.

I haven't time for the last 2 which are really 6 more questions. I'm really rushed today so if you repost them as a separate question, I may have time later on.