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Ahat [919]
2 years ago
7

Keith started saving for retirement at age 45 with plans to retire at age 70. He invested an average of $500 per month in variou

s securities, with an average annual return of 6% adjusted for inflation. Assuming monthly compounding, how much has Keith saved at the start of retirement? (show work)
A= $27,432.26
B= $446,496.98
C= $346,496.98
D= $712,355.15
Mathematics
1 answer:
saveliy_v [14]2 years ago
8 0
500×((1+0.06÷12)^(12×25)−1)÷(0.06÷12)
=346,496.98
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2/9x+-2=6 <br> i need help anyone?
Diano4ka-milaya [45]

Answer:

x = 36

Step-by-step explanation:

We have the equation (2/9)x + -2 = 6.

First, notice that adding a negative number is the same as subtracting by that number. So:

(2/9)x + -2 = 6

(2/9)x - 2 = 6

Now, we need to isolate the variable. Add 2 to both sides to cancel out the -2 on the left:

(2/9)x -2 + 2 = 6 + 2

(2/9)x = 8

Now multiply both sides by 9/2 to cancel out the 2/9 on the left:

(9/2) * (2/9)x = 8 * (9/2)

x = 72/2 = 36

Thus, x = 36.

<em>~ an aesthetics lover</em>

4 0
3 years ago
F(x) = -x - 3 Find f(-4) f(-4) = -(-4) -3
skelet666 [1.2K]

Answer:

\boxed{ \bold{ \boxed{ \sf{f( - 4) = 1}}}}

Step-by-step explanation:

Given, f ( x ) = - x - 3

Let's find the value of f ( - 4 )

\sf{f( - 4) =  - ( - 4) - 3}

We know that , ( - ) \times ( - ) = ( + )

⇒\sf{ 4 - 3}

Subtract 3 from 4

⇒\sf{1}

Hope I helped!

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5 0
2 years ago
In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th
marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}

Where:

\hat{p} is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

z_{\alpha /2} is the critical value needed to find the tails of distribution related to the confidence level,

n is the sample's size.

<u>First</u> we compute the \hat{p} value:

\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

z_{\alpha /2}=2.576

Now we can replace in the formula with the obtained values to compute the confidence interval:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)

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3 years ago
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Dafna11 [192]

Answer:

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Step-by-step explanation:

you have to combine like terms

subtract 4z - 2z and you get 2z

the number with the variable next to it goes first not the constant

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4 0
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What reason does Frederick Lugard use to justify British imperialism?
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His opinion was that christianity needed to be spread

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