Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
Answer:
7. D:61
8. A:57
9. A: 47
Step-by-step explanation:
Quesiton 7:
To find perimeter we add all the sides together.
x+2x+2x+5=145
Combine all the x's.
5x+5=145
To isolate the constants, subtract 5 from both sides.
5x=140
Now divide both sides by 5 to isolate the x.
x=28
The questions asks for the length of AC, so to find that we need to insert our new x.
AC= 2(28)+5
56+5=61
Answer:
The answers are
f
∘
g
(
x
)
=
2
x
2
−
4
x
−
3
And
g
∘
f
(
x
)
=
(
2
x
−
3
)
(
2
x
−
5
)
Explanation:
f
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x
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=
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x
−
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g
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x
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=
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2
x
=
f
(
g
(
x
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)
=
f
(
x
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−
2
x
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=
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(
x
2
−
2
x
)
−
3
=
2
x
2
−
4
x
−
3
g
∘
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
2
x
−
3
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=
(
2
x
−
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)
2
−
2
(
2
x
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=
(
2
x
−
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(
2
x
−
3
−
2
)
=
(
2
x
−
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)
(
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x
−
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)
f
∘
g
(
x
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≠
g
∘
f
(
x
)
Step-by-step explanation:
I search them on goggle..and that's the answer...
Answer:
No. The data shows that it rains more than once in 5 of the 12 months shown. She says she wants it to rain less than an inch every month. And with such a small sample, a mean of 0.9 and a median of 0.7 could change drastically.
