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stepladder [879]
3 years ago
8

A square has side length of 9 in. If the area is doubled, what happens to the side length?

Mathematics
1 answer:
Alika [10]3 years ago
7 0

Answer:

The side length is multiplied by \sqrt{2}

Step-by-step explanation:

we know that

The area of the original square is equal to

A=9^{2}=81\ in^{2}

If the area is doubled

then

The area of the larger square is

A1=(2)81=162\ in^{2}

Remember that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the larger square

y ---> the area of the original square

so

z^{2}=\frac{x}{y}

we have

x=162\ in\^{2}

y=81\ in\^{2}

z^{2}=\frac{162}{81}

z^{2}=2

z=\sqrt{2} ------> scale factor

therefore

The side length is multiplied by \sqrt{2}

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PLS ANSWER WILL MARK BRAINLIEST!<br> (I HAVE 5 MINS)
inysia [295]

Answer: 920 square feet

Step-by-step explanation: Really hope this helps

Top: 20 * 17 = 340

Side triangles: 8 * 15 / 2 = 60

2 side triangles: 60 * 2 = 120

Back rectangle: 8 * 20 = 160

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3 0
2 years ago
If g(x) = -5x + 13, find g(-1)
givi [52]

To solve this problem, we must substitute the value of -1 in for x in the function. This means that for every x there is in the equation, we must substitute the value -1 in for it in order to find the value of g(-1). This is modeled below:

g(x) = -5x + 13

g(-1) = -5(-1) + 13

Next, we must simplify using the order of operations. PEMDAS outlines this concept, telling us to simplify parentheses first, exponents next, then multiplication and division, and finally addition and subtraction. In this case, we will solve the multiplication and then the addition, as modeled below:

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A pool measuring 10 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the po
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Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

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The area of the path can therefore be found to be:

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Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
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In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

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