F(x) = x^2 + 1
f(4) = 4^2 + 1 = 16 + 1 = 17
2*f(4) = 2 * 16 = 32
Answer:
128√5/3 mm³
Step-by-step explanation:
Since we are not told what to find, we can as well look for the volume of the pyramid
Volume of a square pyramid: V = (1/3)a²h
a is the side length of the square
h is the height of the pyramid
Given
a = 8mm
l² = (a/2)² + h²
l² = (a/2)² + h²
6² = (8/2)² + h²
h² = 6² - 4²
h² = 36 - 16
h² = 20
h = √20
Volume of a square pyramid = (1/3)*8²*√20
Volume of a square pyramid = 1/3 * 64 * 2√5
Volume of a square pyramid = 128√5/3 mm³
Answer:
see explanation
Step-by-step explanation:
Given
(x - 3) × (x + 4) = 0, that is
(x - 3)(x + 4) = 0
The zero product indicates that (x - 3) = 0 or (x + 4) = 0
x - 3 = 0 ⇒ x = 3
x + 4 = 0 ⇒ x = - 4
Thus if x = 3, then
(3 - 3)(x + 4) = 0 × (x + 4) = 0
Similarly if x = - 4 the output is zero
X + 3 = 0
2x - 1 = 0
It would be D.
