So.. .at the beginning of the sale, there was a total of "x" pies
now, let's see what happened to those pies
so, we had "x"
then Mary took 2, she left x - 2
Kate took half of that (x-2)/2
then 10 were sold, and 14 leftover
if we subtract all those figures, and solve for "x",
we should get what "x" was, so
notice, if we subtract what Mary took, and Kate, and the sold and leftover, from the original "x", we would end up with no pies :)
so.. just solve for "x"
Answer:
Banana = 6, the rest is in the picture
Step-by-step explanation:
9m is the greatest common monomial factor you can take out of both.
9m(m^2 - 3)
Answer:
Yellow = 5 times and I think you meant blue since there is no purple so blue = 3 times
Step-by-step explanation:
There is ten in all and half of the spaces are yellow, or 50%. Out of ten times, you should land on it about half, or 5. For blue, there are 3 spaces, or 30%. Out of ten times, you should lamd on it about three.
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:
And for this case we can use the Sylow theorems, given by:
Let G a group of order 
where p is a prime number, with 
and p not divide m then:
1) 
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168
