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const2013 [10]
4 years ago
14

"what is the binary equivalent of the decimal value 97?"

Mathematics
1 answer:
AleksandrR [38]4 years ago
5 0
01100001 = 97 64+32+1=97  (if the leading bit is 0 it's usually not shown)
very easy
8 bits
Bit 1 Value 128
Bit 2 value 64
Bit 3 value 32
Bit 4 value 16
Bit 5 value 8
Bit 6 value 4
Bit 7 value 2
Bit  8 value 1
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3x + 1 < −2x + 8
Fantom [35]

Hello there!


The correct answer is B. Why? Well, we cannot choose A, because we don't have a multiplication sign. We cannot choose C because we also don't have a multiplication sign. However, since we have a PLUS sign and a Subtraction sign, we can say that the correct answer is option B.


3x + 1 < -2x + 8

We wanna start by subtracting 1 on both sides

3x + 1 - 1 < -2x + 8 - 1

3x < -2x + 7

Add 2x on both sides

3x + 2x < -2x + 7 + 2x

5x < 7

x < 7/5


I hope this answer helps! As always, it is my pleasure to help students like you. If you have any additional questions, feel free to comment them down below. I'll see you around!

8 0
3 years ago
What is the distance?(-4,2) (-2,-2)
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8 0
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If m 2 n, which inequalities must be true? Check all that apply.
anzhelika [568]

Answer:

(a)\ m+ 2.1 > n + 2.1

(b).\ m - (-4) > n - (-4)

(c)\ 9 +m> 6 + n

Step-by-step explanation:

Given

m > n

Required

Select true inequalities

(a)\ m+ 2.1 > n + 2.1

Subtract 2.1 from both sides

m > n

This is true

(b).\ m - (-4) > n - (-4)

Open brackets

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(c)\ 9 +m> 6 + n

m> -9+6 + n

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This is also true

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3 years ago
Read 2 more answers
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