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Nadya [2.5K]
3 years ago
5

The explicit rule for a sequence is given.

Mathematics
2 answers:
never [62]3 years ago
7 0

Answer:

a_{1} =\frac{2}{5} ,Recursive formula is :

a_{n} =a_{n-1} .5

Step-by-step explanation:

To find a1 we put n=1 in the given Geometric sequence :

a_{1} =\frac{2}{5}5^{1-1}

a_{1} =\frac{2}{5}

a_{2} =\frac{2}{5}5^{2-1} = 2

Common difference = 2÷\frac{2}{5} = 5.

r=5.

Recursive formula for a geometric sequence is  

a_{n} =a_{n-1} .r

Recursive formula is :

a_{n} =a_{n-1} .5

bogdanovich [222]3 years ago
7 0

Answer: a1=2/5 and an= 5an-1

Just took the test, you're welcome

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Rewrite the equation in vertex form. then find the vertex of the graph. y=-3x^2-5x+1
amm1812

Answer: y = -3(x + \frac{5}{6})² + \frac{37}{12}, (-\frac{5}{6}, \frac{37}{12})

<u>Step-by-step explanation:</u>

First, you need to complete the square:

y   = -3x² - 5x + 1

<u> -1  </u>   <u>                -1  </u>

y - 1 = -3x² - 5x

y - 1 = -3(x² + \frac{5}{3}x

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           ↑                     ↓            ↑

                                  \frac{5}{3*2} = (\frac{5}{3*2})^{2}

y - 1 - \frac{25}{12} = -3(x + \frac{5}{6})²

y - \frac{12}{12} - \frac{25}{12} = -3(x + \frac{5}{6})²

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y = -3(x + \frac{5}{6})² + \frac{37}{12}

Now, it is in the form of y = a(x - h)² + k   <em>where (h, k) is the vertex</em>

Vertex = (-\frac{5}{6}, \frac{37}{12})

8 0
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