= (4x^3y^4)/(-8xy^2)
simplify exponents by subtracting the denominator exponent from numerator exponent [x^(3-1)]
= (4x^3y^4)/(-8xy^2)
simplify -4/8 by 4 into numerator and denominator
= (-1x^2y^2)/2
= (-x^2y^2)/2
ANSWER: (-x^2y^2)/2
Hope this helps! :)
20+8=28
16+12=28...
are thus enough
Answer:
![k=-4](https://tex.z-dn.net/?f=k%3D-4)
Step-by-step explanation:
So we have the function:
![f(y)=y^2-ky-5](https://tex.z-dn.net/?f=f%28y%29%3Dy%5E2-ky-5)
And we know that f(2)=7 and we want to find k.
So, substitute 2 for y and 7 for f(y). Thus:
![7=(2)^2-k(2)-5](https://tex.z-dn.net/?f=7%3D%282%29%5E2-k%282%29-5)
Evaluate the square:
![7=4-2k-5](https://tex.z-dn.net/?f=7%3D4-2k-5)
Subtract:
![7=-2k-1](https://tex.z-dn.net/?f=7%3D-2k-1)
Add 1 to both sides:
![8=-2k](https://tex.z-dn.net/?f=8%3D-2k)
Divide both sides by -2:
![k=-4](https://tex.z-dn.net/?f=k%3D-4)
So, the value of k is -4.
And we're done!
0.034 would be the correct answer.