What can you say about the nature of any other zeros of the quadratic equation , which has one complex zero? Explain your answer
1 answer:
According to the fundamental theorem of algebra, a polynomial has the
number of zeros equivalent to the degree of the polynomial.
A quadratic equation is of degree 2 and hence has 2 zeros.
A complex zero is of the form
which represents two zeros: a + bi and a - bi.
Thus, since a quadratic equation has only 2 zeros, a quadratic equation with a complex zero already have two zeros and hence will not have any other zero.
A quadratic equation is of degree 2 and hence has 2 zeros.
A complex zero is of the form
Thus, since a quadratic equation has only 2 zeros, a quadratic equation with a complex zero already have two zeros and hence will not have any other zero.
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1) 6, 18, 54
2) 5/3, 14/9, 41/27
3) 1.5, 2.5, 2.5
Step-by-step explanation:
1)
The function that we have in this problem is
We want to find the first 3 iterations.
The initial value is:
x = 2
To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:
The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:
Finally, the 3rd iteraction is given by:
2)
Here in this problem the function that we have to use is
The initial value is
So the first iteration is given by
To find the 2nd iteration, we substitute this value into g(x) again:
Finally, to find the 3rd iteration, we substitute this value into g(x) again:
3)
The function in this problem is
The initial value is
x = 0.5
So, the first iteration is:
The second iteration is given by
Finally, the 3rd iteration is