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IrinaVladis [17]
3 years ago
13

You want to place a towel bar that is 10 1⁄4 inches long in the center of a door that is 26 1⁄3 inches wide. How far should you

place the bar from each edge of the door?
Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Center of the door

26 1/3 divided by 2

change to an improper fraction

(3*26+1)/3 =79/3

79/3 divided by 2

copy dot flip

79/3 * 1/2

79/6

change to a mixed number

13 1/6

10 1/4 divided by 2

change to an improper fraction (4*10+1)/2 = 41/4

41/4 divided  by 2

copy dot flip

41/4 * 1/2 =41/8

change to a mixed number

5 1/8

the left of the bar should be 5 1/8 from the center

to find how far from the left side to place the bar

13 1/6 - 5 1/8 =

get a common denominator

13 4/24 - 5 3/24= 8 1/24 inches


Answer:  place the bar 8 1/24 inches  from each  edge



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\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad 
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A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &3600\\
r=rate\to 32\%\to \frac{32}{100}\to &0.32\\
t=\textit{elapsed time}\to &5\\
\end{cases}
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A=3600(1-0.32)^5\implies A=3600(0.68)^5\implies A\approx 523.41601
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22 quarts of orange juice is available. How many gallons of orange juice is available?
serg [7]

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7 0
3 years ago
What is the equation of g(x)?
Ksenya-84 [330]

Answer:

g(x)=10^{x-3}

Step-by-step explanation:

Notice that function g(x) has the exat shape of function f(x), and it has just be translated to the right by 3 whole units.

Recall that horizontal translations to the right involve subtracting the number of units moved in the translation from the variable "x". therefore, in our case this means:

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Find the cube root of 27d3 + 54a2b + 36ab2 + 8b3​
enot [183]

Answer:

 (3a + 2b)3

Step-by-step explanation:

STEP 1  :

Equation at the end of step 1

 (((27•(a3))+((54•(a2))•b))+(36a•(b2)))+23b3

Step 2:

(((27•(a3))+((54•(a2))•b))+(22•32ab2))+23b3

Step 3:

(((27•(a3))+((2•33a2)•b))+(22•32ab2))+23b3

Step 4:

 ((33a3 +  (2•33a2b)) +  (22•32ab2)) +  23b3

Step 5:

 Factoring:  27a3+54a2b+36ab2+8b3

8 0
2 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
3 years ago
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