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blsea [12.9K]
3 years ago
5

Kyle and linda are married with two children at home and a mortgage. kyle’s net pay per year is $32,000 and linda’s is $48,000.

their monthly expenses are $3,500. kyle and linda each contribute 15% of their earnings to a retirement fund and they have $5,000 in savings. they also have a $100,000 life insurance policy on kyle, but none on linda. as their financial advisor, what part of kyle and linda’s financial plan would you encourage them to work on and why?
Mathematics
1 answer:
kvv77 [185]3 years ago
5 0
Insurance is needed for Linda more than Kyle as she provides more income (would be more of a financial loss if anything happened to her). Need more life insurance than 100k for Kyle and certainly need even more for Linda. Need Income protection as well. 
<span>They are saving some of their earnings which is great but all in a retirement fund plus 5k in cash. Diversify into property directly perhaps (though as financial adviser this is normally not where you want them to invest) and also some gearing could help substantially.</span>
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Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
3 years ago
Write the equation of a line that passes through the point (-2, 1) and has a slope of 4.
stiv31 [10]

Answer:

y=4x-3

Step-by-step explanation:

y=(slope)x+b

y=4x+b

Insert Point:

1=4(1)+b

b=-3

3 0
3 years ago
What is 11 3\5 + 6 4\15
SOVA2 [1]
So what i would do is take 3/5 and multiply is all by 3 so you end up with 9/15.
Now after you have done that  do this,  9/15+ 4/15. Add 9/15 and 4/15 together which has a sum of 13/15 now add 11 + 6 which is 17 then add in the 13/15 and you get the answer of 17 13/15
8 0
3 years ago
Suppose that administrators of a large school district wish to estimate the proportion of children in the district enrolling in
11Alexandr11 [23.1K]

Answer:

95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.

Step-by-step explanation:

Confidence interval = p + or - zsqrt[p(1-p) ÷ n]

p is sample proportion = 39/60 = 0.65

n is the number of children sampled = 60

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Divide significance level by 2 to obtain critical value (z)

0.05/2 = 0.025 = 2.5%

z at 2.5% significance level = 1.96

zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122

Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528

Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

5 0
3 years ago
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kozerog [31]

9514 1404 393

Answer:

  C.  0.98

Step-by-step explanation:

The attached graph shows the constraints. The feasible solution space is the doubly-shaded area in the first quadrant. The negative coefficients on x and y suggest that the objective function will be maximized when x and y are minimized. The solution space vertex that does that is ...

  (x, y, Y) = (6, 4, 0.98)

7 0
3 years ago
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