Answer
Find out the how many cats were at the shelter on Thursday .
To prove
let us assume that the number of cats in the animal shelter be x.
let us assume that the number of dogs in the animal shelter be y.
As given
An animal shelter spends $5.00 per day to care for each cat and $7.00 per day to care for each dog.
Brayden noticed that the shelter spent $193.00 caring for cats and dogs on Thursday.
Than the equation becomes
5x + 7y = 193
Brayden found a record showing that there were a total of 29 cats and dogs on Thursday.
Than the equation becomes
x + y = 29
Than two equation are
5x + 7y = 193 , x + y = 29
Multiply x + y = 29 by 7 and subtrscted from 5x + 7y = 193 .
5x - 7x + 7y - 7y = 193 - 203
5x - 7x = 193 - 203
-2x = -10
x = 5
Therefore the number of cats are 5 on Thursday .
Answer:
Step-by-step explanation:Hm... I think you should do the question on your own. Don’t you think. Because I am a teacher. I would be revealing the answer away, and that is not the way teachers role, so please do the question on your own. But it is ok. If you don’t want to, like I said you don’t have to. But it would be great. Not trying to start a fight...but... I will just stop talking, bye. Have nice day, stay curious.
Answer:
no he is not correct
Step-by-step explanation:
Answer:
An expression is shown below:
10n³− 15n² + 20xn² − 30xn
Part A: Rewrite the expression so the GCF is factored completely. (4 points)
10n³− 15n² + 20xn² − 30xn
2*5*n*n*n-5*3*n*n+2*5*2*x*n*n-2*5*3*x*n
<u>Greatest</u><u> </u><u>common</u><u> </u><u>factor</u><u>=</u><u>5</u><u>*</u><u>n</u><u>=</u><u>5</u><u>n</u>
Part B: Rewrite the expression completely factored. Show the steps of your work.
Solution given;
10n³− 15n² + 20xn² − 30xn
5n(2n²-3n+4xn-6x)
5n(2n²+4xn-3n-6x)
5n(2n(n+2x)-3(n+2x))
<u>5n(n+2x)(2n-3</u>)