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kolbaska11 [484]
3 years ago
10

What is the cross section of a rectangular prism​

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

The cross section is just at the center of the rectangle. Sorry if I couldn't be of more help but good luck.

Step-by-step explanation:

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A bag contains 135 marbles some white and some transparent. The ratio of white marbles to transparent ones is 3 : 6. How many wh
Setler [38]

Answer:

Number of white marbles in the bag = 45

Step-by-step explanation:

Total number of marbles in the bag = 135

Ratio of white marble to transparent ones = 3 : 6

Let number of white marbles be =3k

Then number of transparent marble will be =6k

Total number of marbles will be =3k+6k=9k

So we have.

9k=135

Dividing both sides by 9.

\frac{9k}{9}=\frac{135}{9}

∴ k=15

∴ Number of white marbles in the bag = 3k=3\times15 = 45

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Sequence 1: 32, 16, 0, –16, ...
vampirchik [111]

This is a cool one. Sequence 1 will approach negative infinity and Sequence 2 will approach 0 but never get to it!

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3 years ago
A cereal box is an example of_____ and ________
gayaneshka [121]
A cereal box is an example of a rectangular prism and a rectangle.
3 0
3 years ago
A ja ja ja ibsnisbisnobs
deff fn [24]

Answer:

20

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
4 years ago
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