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kirill115 [55]
3 years ago
13

20. A cheetah can chase after its prey at

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:80.28

Step-by-step explanation:80+0.28miles

that will give you

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what is the rate of change and initial value for this graph?
MAXImum [283]

Answer:

4/7

Step-by-step explanation:

the rate of change (aka slope) is the change in y over change in x and as y goes up 4 x goes up 7 so the rate of change is 4/7

have a great day :D

8 0
3 years ago
I’m very bored and I want to learn something. Tell me something cool like a fun fact or a joke and the best one gets Brainliest!
lbvjy [14]
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7 0
3 years ago
Read 2 more answers
Can I have some help on these two math questions?
BigorU [14]
8. 1,728 i did 12×18÷2=108×32=345÷2= 1,728
8 0
4 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
3 years ago
Solve the equation for x.
DiKsa [7]
You multiply 0.6 by 5x and 10 and you get 3x+6=-24. you then subtract 6 from both sides of the equation and you get 3x=-30. after that you divide both sides by 3 and you get x=-10. so the answer is B!
6 0
3 years ago
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