the equation of a line in point-slope form is
y - b = m(x - a)
where m is the slope and (a, b ) is a point on the line
y + 1 = (x + 5) is in this form
(a) with slope =
(b) point on the line = (- 5, - 1 ) = (a, b)
Answer:
0=−2
Step-by-step explanation:
espero que esto ayude! y que Dios te bendiga .. mantente a salvo!
hope this is helpful God Bless you stay safe!
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:2x+28 100% right
Step-by-step explanation: